2. Consider the following 13C NMR (20 pts) i The signals at 132 and 144 ppm correspond to the a and ß carbons respective

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2. Consider the following 13C NMR (20 pts) i The signals at 132 and 144 ppm correspond to the a and ß carbons respective

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2 Consider The Following 13c Nmr 20 Pts I The Signals At 132 And 144 Ppm Correspond To The A And Ss Carbons Respective 1
2 Consider The Following 13c Nmr 20 Pts I The Signals At 132 And 144 Ppm Correspond To The A And Ss Carbons Respective 1 (19.56 KiB) Viewed 44 times
2 Consider The Following 13c Nmr 20 Pts I The Signals At 132 And 144 Ppm Correspond To The A And Ss Carbons Respective 2
2 Consider The Following 13c Nmr 20 Pts I The Signals At 132 And 144 Ppm Correspond To The A And Ss Carbons Respective 2 (31.03 KiB) Viewed 44 times
2. Consider the following 13C NMR (20 pts) i The signals at 132 and 144 ppm correspond to the a and ß carbons respectively. Briefly explain why the B carbon is more deshielded than the a carbon. 120 PPM 20 0
Product (C5H120): 1H NMR: singlet, 4.5 ppm, 1H; quartet, 1.4 ppm, 2H; singlet, 1.20 ppm, 6H; triplet, 0.90 ppm, 3H 80 70 60 50 PPM 40 PPM 30 20 10
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