- 4 5 3 2 1000 6 5 Points Consider The Equation 2a 3b 2c Ago A 51 09 Kj Mol Ago B 205 70 Kj Mol Ago C 71 68kj Mo 1 (11.31 KiB) Viewed 33 times
4 5 3 2 1000 6 5 points Consider the equation: 2A+ 3B->2C AGO (A) 51.09 kJ/mol AGO (B)=-205.70 kJ/mol AGO (C)-71.68kJ/mo
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4 5 3 2 1000 6 5 points Consider the equation: 2A+ 3B->2C AGO (A) 51.09 kJ/mol AGO (B)=-205.70 kJ/mol AGO (C)-71.68kJ/mo
4 5 3 2 1000 6 5 points Consider the equation: 2A+ 3B->2C AGO (A) 51.09 kJ/mol AGO (B)=-205.70 kJ/mol AGO (C)-71.68kJ/mol Calcualte AGº for this reaction at 298K in kJ. Report your answer with 2 places past the decimal point.