For The Following Reaction 0 478 Moles Of Hydrogen Gas Are Mixed With 0 315 Moles Of Ethylene C H4 Hydrogen G Et 1 (16.82 KiB) Viewed 29 times
For The Following Reaction 0 478 Moles Of Hydrogen Gas Are Mixed With 0 315 Moles Of Ethylene C H4 Hydrogen G Et 2 (14.52 KiB) Viewed 29 times
For the following reaction, 0.478 moles of hydrogen gas are mixed with 0.315 moles of ethylene (C₂H4). hydrogen (g) + ethylene (C₂H₁) (9)→ ethane (C₂H6) (9) What is the formula for the limiting reactant? What is the maximum amount of ethane (C₂H6) that can be produced? Amount = mol
For the following reaction, 0.151 moles of diphosphorus pentoxide are mixed with 0.318 moles of water. diphosphorus pentoxide(s) + water() → phosphoric acid (aq) What is the formula for the limiting reactant? What is the maximum amount of phosphoric acid that can be produced? mol Amount =
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