You would like to determine the mutation responsible for segregation of familial hypertrophic cardiac myopathy in the pe

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You Would Like To Determine The Mutation Responsible For Segregation Of Familial Hypertrophic Cardiac Myopathy In The Pe 1 (30.57 KiB) Viewed 23 times

You Would Like To Determine The Mutation Responsible For Segregation Of Familial Hypertrophic Cardiac Myopathy In The Pe 2 (34.33 KiB) Viewed 23 times

You Would Like To Determine The Mutation Responsible For Segregation Of Familial Hypertrophic Cardiac Myopathy In The Pe 3 (34.33 KiB) Viewed 23 times

You would like to determine the mutation responsible for segregation of familial hypertrophic cardiac myopathy in the pedigree below. You test three SNP markers from three different chromosomal regions: an SNP 50 kbp from the troponin T gene on 1q, an SNP in the promoter of the myosin heavy chain gene on 14q, and an SNP in intron 3 of the tropomyosin gene on 15q. A AA * A 1. M # Which marker gives the lowest LOD * score for linkage at != 0 to the disease locus? Explain your answer. Your answer Which marker gives the highest LOD score for linkage at != 0 to the disease locus? Explain your answer. Note: It is not necessary to solve the LOD score mathematically to answer part (a) and (b). Votre réponse What is the LOD score at != 0 for linkage between the 1q marker and the disease locus? Votre réponse
III-4 Aa BB III-5 Aa BB III-6 aa Bb 888 a. Which marker gives the highest LOD score for linkage at 0 = 0 to the disease locus? Explain your answer. Note: It is not necessary to solve the LOD score mathematically to answer part (a) and (b). Iq- there are no recombination events for the disease gene a. Therefore lq has the highest LOD score (5 points). III-1 III-2 III-3 III-4 111-5 III-6 b. Which marker gives the lowest LOD score for linkage at 0=0 to the disease locus? Explain your answer. 14q has the lowest LOD score, and is not linked (4 recombination events) (5 points). The meioses of 15q is uninformative. LOD= (1-0) (1/2) 4 c. What is the LOD score at 8=0 for linkage between the 1q marker and the disease locus? =log 64 = 1.8 (10 points) =log (1)*(0)" (1/2)