The reaction of peroxydisulfate ion (S2O82−) with iodide ion (I−) is S2O82−(aq) + 3I−(aq) → 2SO42−(aq) + I3−(aq) From

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answerhappygod
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The reaction of peroxydisulfate ion (S2O82−) with iodide ion (I−) is S2O82−(aq) + 3I−(aq) → 2SO42−(aq) + I3−(aq) From

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The reaction of peroxydisulfate ion(S2O82−) with iodide ion(I−) isS2O82−(aq) +3I−(aq) → 2SO42−(aq)+ I3−(aq)From this data collected at a certain temperature, calculate therate constant.k = ____ 1/Ms
[S2O82−]
[ I− ]
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