E = 2 expi[kx-ot +15°] +2ŷ expi [kx-at-75°] V/m. x, ŷ e 2 Co = c/k i=√1.

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answerhappygod
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E = 2 expi[kx-ot +15°] +2ŷ expi [kx-at-75°] V/m. x, ŷ e 2 Co = c/k i=√1.

Post by answerhappygod »

E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 1
E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 1 (4.3 KiB) Viewed 16 times
E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 2
E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 2 (1.01 KiB) Viewed 16 times
a) Write the equation of the magnetic field vector H of thiswave in complex form;
E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 3
E 2 Expi Kx Ot 15 2y Expi Kx At 75 V M X Y E 2 Co C K I 1 3 (795 Bytes) Viewed 16 times
c) Consider now that the wave described above crosses aquarter-wave sheet with principal axes in the y and z directions.Determine the polarization state of the light at the exit of theslide. Justify your answer.
E = 2 expi[kx-ot +15°] +2ŷ expi [kx-at-75°] V/m.
x, ŷ e 2
Co = c/k
i=√1.
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