A rectangular loop of wire is w = 2.70 cm wide, L = 30.0 cm long, and is located d = 2.00 cm from a long. straight wire

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answerhappygod
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A rectangular loop of wire is w = 2.70 cm wide, L = 30.0 cm long, and is located d = 2.00 cm from a long. straight wire

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A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 1
A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 1 (58.14 KiB) Viewed 18 times
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A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 2
A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 2 (45.13 KiB) Viewed 18 times
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A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 3
A Rectangular Loop Of Wire Is W 2 70 Cm Wide L 30 0 Cm Long And Is Located D 2 00 Cm From A Long Straight Wire 3 (54.62 KiB) Viewed 18 times
A rectangular loop of wire is w = 2.70 cm wide, L = 30.0 cm long, and is located d = 2.00 cm from a long. straight wire that carries wire = 40.0 A of current as shown in the figure. Assume a current of 20.0 A in the loop. What is the magnitude Foct of the net force on the rectangular loop? What is the direction of the net force on the rectangular loop? left 000 up down into the screen out of the screen Oright Fnet wire 1.2 X10-3 Incorrect W N
In the mass spectrometer shown in the figure, a particle with charge -e = -1.60 x 10-19 Centers a region of magnetic field Be that has a strength of 0.00297 T and points into the screen. The velocity of the particle is confirmed with a velocity selector. The electric field E is 9.00 x 10¹ V/m (down) and the magnetic field By is 0.00590 T (into screen) in the velocity selector. If the radius r of curvature of the particle is 4.00 cm, calculate the mass m of the particle. Velocity Selector 8 tot t HOLA m= Ⓡ Bc Ⓡ Ⓡ Ⓡ Ⓡ 80 kg
A 300-turn wire loop with a 5.0 cm radius is connected to a 0.20-kg pulley by a lightweight rod. The pulley, which has a radius of 3.1 cm, is attached to a 4.1-kg block by a massless rope, as shown in the figure. The loop is in a 0.75-T magnetic field. When no current flows through the wire loop, the plane of the loop is parallel to the magnetic field, and the block attached to the pulley just touches the ground. However, when a 0.83-A current flows through the loop, magnetic forces cause the loop to rotate, which lifts the block off the ground. Calculate the equilibrium angle of plane of the loop relative to the magnetic field. To what height y off the ground is the block lifted? 0= y N S m
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