Consider the capacitor in image (a) below with an area A=68 m^2, a plate separation d=4.89 m, and air as the dielectric.

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answerhappygod
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Consider the capacitor in image (a) below with an area A=68 m^2, a plate separation d=4.89 m, and air as the dielectric.

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Consider The Capacitor In Image A Below With An Area A 68 M 2 A Plate Separation D 4 89 M And Air As The Dielectric 1
Consider The Capacitor In Image A Below With An Area A 68 M 2 A Plate Separation D 4 89 M And Air As The Dielectric 1 (26.08 KiB) Viewed 28 times
Consider The Capacitor In Image A Below With An Area A 68 M 2 A Plate Separation D 4 89 M And Air As The Dielectric 2
Consider The Capacitor In Image A Below With An Area A 68 M 2 A Plate Separation D 4 89 M And Air As The Dielectric 2 (10.68 KiB) Viewed 28 times
Consider the capacitor in image (a) below with an area A=68 m^2, a plate separation d=4.89 m, and air as the dielectric. A dielectric is then added with a relative permittivity of e, -8.7, as shown in image (c) below. What is the ratio of the capacitance of the capacitor in image (c) to the capacitor in image (a)? H +++++ V (a) Dielectric ***** .. - A (b) ********** V (c)
Consider a capacitor with a plate separation of d=1.57 m. If the dielectric used in the capacitor has a breakdown field of 2,389 V/m, what is the MAXIMUM voltage which could be applied while avoiding a breakdown condition? Provide your answer in V.
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