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answerhappygod
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please solve complete in one hour

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please solve complete in one hour
Please Solve Complete In One Hour 1
Please Solve Complete In One Hour 1 (93.04 KiB) Viewed 25 times
Task 2 (20 points) In a lighter, the fuel butane is typically present in two phases. In simplified terms, the fuel container of the lighter shown opposite can be described as a cuboid. The base area is square with a side length of a = 3.0 cm. The height of the cuboid is h = 6.0 cm. In state 1, the fire has produces a temperature of t1 = 15.0 C The The vapour content of the butane is xi = 0.04. h hP G V Hint: Round the results to three decimal places (e.g. 1023.300, 58.189 or 0.015) unless otherwise stated. a) b) What is the pressure p in the system in state 1 (in bar)? [ Determine the density of the liquid p'; and the density of the gas pin state 1 (both in kg/m3). Determine the total mass mi of butane in state 1 (in g). [ At what height hp, is the phase boundary in state 1 (in cm)? c) d) In the following parts of the task, continue calculating exclusively with the following values for state 1. The geometric dimensions do not change. mi pl 3.801 g 572.8 kg/m3 ρι p! 70.39 kg/m3 6.172 kg/m3 X1 0.0777 2.43 bar pi ti 25.00 e) The housing of the lighter can just withstand a pressure of Pberst = 40 bar. At what temperature Tberst is this pressure reached if the total mass mı does not change? (in K)? What is the maximum amount of lo2tilbe added to the butane from state 1 until the container bursts (state 2) (in kJ)? f)

g) After n = 953 candles have been lit with the lighter, there is only just saturated gas in them (state 3). The supply The change in temperature 13 was isothermal. How many millilitres of butane gas have left the container per candle on average (in ml)? What quantity of 13 must be added to the butane for this change of state ( 13) (in kJ)? h) Notes: - Abbreviation: PG (phase boundary) - Substance data can be taken from the following two tables. If necessary, interpolate linearly. Substance data butane Critical data Butane: tcrit = 152.0 Perit = 228.0 kg/m3; Perit = 37.96 bar Single-phase tp S P kg/m3 58.89 h kJ/kg 1161.2 kJ/(kg K) 3.341 40.0 40.0 60.07 3.308 Cbar 281.25 275.10 233.47 184.08 156.18 299.83 293.19 248.08 40.0 40.0 70.39 95.82 1142.9 1019.9 868.6 3.075 2.760 40.0 183.21 58.89 2.449 3.430 42.0 60.07 731.4 1214.6 1194.5 1059.7 893.5 42.0 42.0 3.395 70.39 95.82 3.147 2.810 193.59 42.0 160.20 42.0 183.21 742.6 2.472 Two-phase tpp Cbarkg/m3 1.24 595.3 1.48 589.8 p! kg/m3 3.278 h! kJ/kg 211.6 kJ/kg 592.4 5.0 10.0 223.4 599.5 3.873 4.549 15.0 1.76 584.3 235.3 5.313 20.0 25.0 2.08 2.43 578.6 572.8 247.3 259.5 606.7 613.8 620.9 628.1 30.0 2.83 567.0 6.172 7.137 8.215 271.8 35.0 284.2 3.28 3.78 561.0 554.9 635.2 642.3 40.0 9.418 296.8 5
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