please solve complete in one hour

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answerhappygod
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please solve complete in one hour

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please solve complete in one hour
Please Solve Complete In One Hour 1
Please Solve Complete In One Hour 1 (141.84 KiB) Viewed 32 times
Please Solve Complete In One Hour 2
Please Solve Complete In One Hour 2 (57.3 KiB) Viewed 32 times
In this task, various ideal gases are considered. If no other information is given, the specific gas constant R = 265.0 J/(kg K). Unless otherwise stated, all changes of state ebe regarded as quasi-static and take place in a closed system. All parts of the task de solved independently of each other. Indices indicate the initial state (index 1) and the final state (index 2). The general gas constant Rm = 8.314462 /(mol K) applies to the entire task. Hint: - Round the results to three decimal places (e.g. 58.189 or 0.015). a) An ideal gas with p = 2201.7 mbar and T = 17.0 K is in a container with a volume of V = 750 cm3. What quantity of substance (in mol) is in the container? b) c) d) What is the pressure p2 (in kPa) after an isothermal change of state (T = 279.4 K), in which a specific volume of v. = 0.08 m3/kg is initially present and 1912 1 = 121 kJ/kg specific heat is dissipated? Three ideal gases were mixed in a closed container. The mixture has a pressure of p = 4.1 bar, the mole fraction of component 1 is . < 0.4 and the partial pressure of component 3 is ps = 2.255 bar. What valbe the pressure (in bar) that would prevail if component 2 occupied the entire container alone (components 1 and 3 wereremoved from the container)? An ideal gas (T. = 550 K, v = 1.91 m3/kg, k = 1.4) is adiabatically and reversibly compressed to a pressure of P2 = 392 kPa. What is then the specific volume (in m3/kg)? A dgnedium is to be selected for the design of a heat exchanger with adiabatic external walls. Since the installation space is limited, the mass flow of the cold gas is only one tenth of the warm mass flow. Nevertheless, the warm mass flow is to be cooled by 210 K, while the cold mass flow is heated by 51 K. The mass flow of the cold gas is to be cooled by the same amount. What must be the ratio of the isobaric lapacities Cp,kalt / Cpwarm? Two stationary flow processes are coupled and the given technical work of a reversible isochoric pressure reduction from pi = 3.5 MPa to p2 = 2.1 MPa at di = 0.4 m3/kg becomes 95% of an isochoric pressure reduction. tropical compression ( 34) is added. What is the pressure ratio pa lp 23 achieved during isentropic compression (t3 = 205.7", K = 1.41)? e) f)

g) h) Starting from vi = 50 cm3/mol and Ti = 399 K, the molar volume of an ideal gas is reduced isobarically by 31%. What is the temperature T2 (in K)? Volumetric work is added to and heat is removed from a closed system. This reduces the temperature by 40 K. Technical work is added to a stationary, open system and the same amount of lemoved as in the closed system. The temperature change is also identical. What is the difference in amount between the volume change and the technical work (in J/kg)? A stationary adiabatic flow process emits W1,12 = 222 kJ/kg and has a dissipation of W1,12,diss = 36 kJ/kg. What is the isentropic exponent of the working medium that is cooled from Ti = 379 K to T2 = 215 K? i)
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