Given the maps: 1) xn+1 = yn yn+1 = 1 - a (yn)2 + b xn 2) xn+1 = 1 - a (xn)2 + b xn-1 3) un+1 = vn vn+1 = a - (vn)2 +

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Given the maps:
1) xn+1 = yn
yn+1 = 1 - a
(yn)2 + b xn
2) xn+1 = 1 - a
(xn)2 + b xn-1
3) un+1 =
vn
vn+1 = a -
(vn)2 + b vn
4) xn+1 = byn
yn+1 = 1 - a
(yn)2 + xn
which of these are equivalent?