MON Case : Observations (in minutes) Performance Job Element 4 5 Rating (A) 8 10 21* 11 120% (B) 3 1 3 105% (C) 2 1 2 1

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Mon Case Observations In Minutes Performance Job Element 4 5 Rating A 8 10 21 11 120 B 3 1 3 105 C 2 1 2 1 1 (136.58 KiB) Viewed 31 times

MON Case : Observations (in minutes) Performance Job Element 4 5 Rating (A) 8 10 21* 11 120% (B) 3 1 3 105% (C) 2 1 2 1 110% 1. Delete all unusual or nonrecurring observations, such as those marked with an asterisk. (They might be due to an unscheduled business interruption, a conference with the boss, or a mistake of an , a unusual nature; these are not part of the job). 2. Compute the average cycle time for each job element. . 8 + 10 + 9 + 11 + + 9 Average time for A = A = 9.5 minutes 2+ +2+ 2 + 3 + 2 + 1 + 3 5 Average time for B 2.2 minutes 2 + 1 + 2 + 1 1 2 + Average time for C- C- 4 1.5 minutes 3. Compute the normal time for each job element. Normal time for A = (average time) x (rating) ) = (9.5) (1.20) 11. 4 minutes Normal time for B = (2.2) (1.05) = 2. 31 minutes Normal time for C = (1.5) (1.10) 1. 65 minutes Normal times are computed for each element because the rating factor may vary for each element, which it , did in this case. . 4. Add the normal times for each element to find the total normal time (the normal time for the whole job). Total normal time – 11.40 + 2.31 + 1.65 = 15.36 minutes = + 5. Compute the standard time for the job. total normal time 15.36 Standard time = 18.07 minutes 1 - allowance factor 1 0.15 1 - Thus 18.07 minutes is the time standard for this job.