The solution of the boundary value problem (D2 +42)y=0,given that y(0) = 0 and y T = 1 Oy = cos 4 y = 3 sin 42 y = 4 sin

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answerhappygod
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The solution of the boundary value problem (D2 +42)y=0,given that y(0) = 0 and y T = 1 Oy = cos 4 y = 3 sin 42 y = 4 sin

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The Solution Of The Boundary Value Problem D2 42 Y 0 Given That Y 0 0 And Y T 1 Oy Cos 4 Y 3 Sin 42 Y 4 Sin 1
The Solution Of The Boundary Value Problem D2 42 Y 0 Given That Y 0 0 And Y T 1 Oy Cos 4 Y 3 Sin 42 Y 4 Sin 1 (15.97 KiB) Viewed 28 times
The solution of the boundary value problem (D2 +42)y=0,given that y(0) = 0 and y T = 1 Oy = cos 4 y = 3 sin 42 y = 4 sin 4. Oy=sin 4.0
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