A department store chain has up to $18.000 to spend on television advertising for a sale. All ads will be placed with on

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A Department Store Chain Has Up To 18 000 To Spend On Television Advertising For A Sale All Ads Will Be Placed With On 1 (25.81 KiB) Viewed 16 times

A department store chain has up to $18.000 to spend on television advertising for a sale. All ads will be placed with one television station, where a 30-second ad costs $1,000 on daytime TV and is viewed by 14,000 potential customers, $2.000 on prime-time TV and is viewed by 24,000 potential customers, and $1,500 on late-night TV and is viewed by 18.000 potential customers. The television station will not accept a total of more than 15 ads in all three time periods. How many ads should be placed in each time period in order to maximize the number of potential customers who will see the ads? How many potential customers will see the ads? (ignore repeated viewings of the ad by the same potential customer.) Include an interpretation of any nonzero slack variables in the optimal solution Select the correct choice below and fit in any answer boxes present in your choice. OA The maximum number of potential customers who see the ads is OB. There is no way to maximize the number of potential customers Include an interpretation of any nonzero slack variables in the optimal solution. OA. In this case, a, 4,000 dollars not used and s₂ -10 ads not used OB. In this case, 8, 10 dollars not used OC. In this case, 4.000 ads not used OD. There are no nonzero slack variables in the optimal solution people when daytime ads prime-sime ads, and late-night ads are placed