The equations that must be solved for maximum or minimum values of a differentiable function w=f(x,y,z) subject to two c

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The Equations That Must Be Solved For Maximum Or Minimum Values Of A Differentiable Function W F X Y Z Subject To Two C 1 (65.18 KiB) Viewed 12 times

The equations that must be solved for maximum or minimum values of a differentiable function w=f(x,y,z) subject to two constraints g(x,y,z) = 0 and h(x,y,z) = 0, where g and h are also differentiable, are Vf=Vg+uVh, g(x,y,z) = 0, and h(x,y,z) = 0, where > and μ (the Lagrange multipliers) are real numbers. Use this result to find the maximum and minimum values of f(x,y,z) = x² + y² + z² on the intersection between the cone z² = 9x² +9y² and the plane 2x + 4z = 5. Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. O A. The maximum value is OB. The minimum value is OC. The maximum value is There is no minimum value. O D. There is no maximum value and no minimum value. The minimum value is There is no maximum value. (...)