Three bulbs A circuit is made of two 1.7 volt batteries and three light bulbs as shown in the figure. When the switch is

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

Three bulbs A circuit is made of two 1.7 volt batteries and three light bulbs as shown in the figure. When the switch is

Post by answerhappygod »

Three Bulbs A Circuit Is Made Of Two 1 7 Volt Batteries And Three Light Bulbs As Shown In The Figure When The Switch Is 1
Three Bulbs A Circuit Is Made Of Two 1 7 Volt Batteries And Three Light Bulbs As Shown In The Figure When The Switch Is 1 (60.09 KiB) Viewed 44 times
Three bulbs A circuit is made of two 1.7 volt batteries and three light bulbs as shown in the figure. When the switch is closed and the bulbs are glowing, bulb 1 has a resistance of 12 ohms, bulb 2 has a resistance of 36 ohms, bulb 3 has a resistance of 25 ohms, and the copper connecting wires have negligible resistance. You can also neglect the internal resistance of the batteries. Bulb 2 Bulb 1 Bulb 3 (a) With the switch open, indicate the approximate surface charge on the circuit diagram.(Do this on paper. Your instructor may ask you to turn in this work.) Refer to your diagram to decide which of the following statements about the circuit (with the switch open) are true: There is a large gradient of surface charge between locations M and L. The surface charge on the wire at location B is positive. The electric field in the air between locations B and C is zero. The electric field in the filament of bulb 3 is zero. There is no excess charge on the surface of the wire at location C. (b) With the switch open, find these potential differences: VB - VC Vp - VK =
(c) After the switch is closed and the steady state is established, the currents through bulbs 1, 2, and 3 are 11, 12, and 13 respectively. Which of the following equations are correct loop or node equations for this steady state circuit? 11 = 12 + 13 12-13 +3.4V + -11*(122) + -12* (362) = 0 +3.4V + -11*(122) + 13*(122) = 0 -11*(1212)-12*(36 12) + 13*(25 $) = 0 -12*(36 2) + 13"252) = 0 (d) In the steady state (switch closed), which of these are correct? VL-VA = -3.4V + 11*(122) VC-VF = 0 Vc - VF = +12 (362) Vc - VF = +11*(122) Vc - VF = +13* (252) (f) Now find the unknown currents, to the nearest milliampere. (I.e. enter your answer to three decimal places.) 11 = A 12 = A 13 = (9) How many rons leave the battery at location N every ond? electrons/s (0) What is the numerical value of the power delivered by the batteries? P = W C) The tungsten filament in the 36 ohm bulb is 8 mm long and has a cross-sectional area of 2 x 10-10 m2. What is the magnitude of the electric field inside this metal filament? V/m
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply