108:26 LHC2222 102 25-5 98d5ed2bc0d 98d5ed2be POPCP SPEE 9ad5ed2bc0d 2 The average cod in line for the, 16,000 daily pas

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answerhappygod
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108:26 LHC2222 102 25-5 98d5ed2bc0d 98d5ed2be POPCP SPEE 9ad5ed2bc0d 2 The average cod in line for the, 16,000 daily pas

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108 26 Lhc2222 102 25 5 98d5ed2bc0d 98d5ed2be Popcp Spee 9ad5ed2bc0d 2 The Average Cod In Line For The 16 000 Daily Pas 1
108 26 Lhc2222 102 25 5 98d5ed2bc0d 98d5ed2be Popcp Spee 9ad5ed2bc0d 2 The Average Cod In Line For The 16 000 Daily Pas 1 (46.33 KiB) Viewed 13 times
108:26 LHC2222 102 25-5 98d5ed2bc0d 98d5ed2be POPCP SPEE 9ad5ed2bc0d 2 The average cod in line for the, 16,000 daily passengers of a roller coaster is 72 minutes with a standard. deviation of 15 minutes. Assume that bet 2.35% abt the data are normally distributed. What percentage of passengers wait between 72 minutes and 87 minutes to ride the roller coaster? 13.5% 95d5ed26 ..2-2021 34% السل الدراسي الثالث ه - 2 - - - - - 34% 13.5% H + 0 + 20 Anormal distribution with mean and standard deviation o 92P*SPB6 + 30 16% 0 تومي في اليوم يساوي القطار لعدد متوسط وقت انتظار 16,000 راكب لقطار 72 دقيقة بانحراف معياري يساوي 15 دقيقة. افترض أن البيانات موزعة توزيعا طبيعيا، ما النسبة المئوية لعدد الركاب الذين ينتظرون بين 72 دقيقة و 87 دقيقة لركوب قطار الملاهي؟ bcod 00000000 42604 2.35% = 30 34% 13.5% - 20 - 34% P059228 826 2.35% Activate 13.5% 4+0+20 +30 التوزيع الطبيعي في الوسط ا والانحراف المعياري - 98d5ed2b 98d5ed2bc0d posazpSPE 98d5ed2bc0d Add Wo
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