- The Solution Of A Certain Differential Equation Is Of The Form Y T A Exp Lt Bexp 3t Where A And B Are Constants 1 (9.59 KiB) Viewed 13 times
The solution of a certain differential equation is of the form y(t) = a exp(lt) + bexp(3t), where a and b are constants.
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The solution of a certain differential equation is of the form y(t) = a exp(lt) + bexp(3t), where a and b are constants.
The solution of a certain differential equation is of the form y(t) = a exp(lt) + bexp(3t), where a and b are constants. The solution has initial conditions y(0) = 5 and 3/(0) = 4. Find the solution by using the initial conditions to get linear equations for a and b. y(t) =