A photo of a simple toy yo-yo yo-yo fixed hand string moves downward A simple yo-yo (photo shown above, right) is an int

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answerhappygod
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A photo of a simple toy yo-yo yo-yo fixed hand string moves downward A simple yo-yo (photo shown above, right) is an int

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A Photo Of A Simple Toy Yo Yo Yo Yo Fixed Hand String Moves Downward A Simple Yo Yo Photo Shown Above Right Is An Int 1
A Photo Of A Simple Toy Yo Yo Yo Yo Fixed Hand String Moves Downward A Simple Yo Yo Photo Shown Above Right Is An Int 1 (69.45 KiB) Viewed 10 times
A photo of a simple toy yo-yo yo-yo fixed hand string moves downward A simple yo-yo (photo shown above, right) is an interesting toy for demonstrating physics principles. The string of a yo-yo of given mass M is wound up on the central axle. The inner axle has a given radius R. The yo-yo as a whole has a total rotational inertia Igoyo = CMR² where Cis a given (known) positive constant that depends on the exact shape of the yo-yo. (The outer radius of the yo-yo is not specified.) Suppose the wound-up yo-yo is released from rest from a fixed hand as show (above, right). The yo-yo immediately begins to accelerate straight downward toward the floor as the string un- winds. Assume the string is ideal and does not slip or slide on the yo-yo axle. Part (a)-: Draw a "Free Body Diagram" indicating all of the forces on the yo-yo. Also draw an "Extended Free Body Diagram" for the yo-yo. Be sure that your FBD and your XFBD each include all of the forces and an appropriately chosen coordinate system. Part (b): Calculate the magnitude of the linear acceleration of the yo-yo. Also calculate the magnitude of the Tension in the ideal string. Show your work. Explain what you are doing. Give your answer in terms of the given parameters. Hint: The magnitude of the acceleration is not equal to g. Another hint: The Tension is not equal to Mg. Yet another hint: There exists a kinematic constraint that applies here which connects the downward linear acceleration of the yo-yo to the rotational acceleration of the yo-yo.
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