0.94 = 0.80 - 0.0592 2 [H+] = 4.3 x 10-³ M pH = 2.4 log [H+]² (1.0)²

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answerhappygod
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0.94 = 0.80 - 0.0592 2 [H+] = 4.3 x 10-³ M pH = 2.4 log [H+]² (1.0)²

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0 94 0 80 0 0592 2 H 4 3 X 10 M Ph 2 4 Log H 1 0 1
0 94 0 80 0 0592 2 H 4 3 X 10 M Ph 2 4 Log H 1 0 1 (14.24 KiB) Viewed 11 times
0.94 = 0.80 - 0.0592 2 [H+] = 4.3 x 10-³ M pH = 2.4 log [H+]² (1.0)²
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