- Part 1 Of 2 A 0 842 Kg Particle Has A Velocity Vasak Ai Bj Where A 0 123 M S And B 4 21 M S And A 4 38 Kg Partic 1 (32.54 KiB) Viewed 13 times
part 1 of 2 A 0.842 kg particle has a velocity Vasak= ai+bj, where a = -0.123 m/s and b = 4.21 m/s, and a 4.38 kg partic
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part 1 of 2 A 0.842 kg particle has a velocity Vasak= ai+bj, where a = -0.123 m/s and b = 4.21 m/s, and a 4.38 kg partic
part 1 of 2 A 0.842 kg particle has a velocity Vasak= ai+bj, where a = -0.123 m/s and b = 4.21 m/s, and a 4.38 kg particle has a velocity U₁3kg =ci+dj, where c = 0.397 m/s and d = 7.8 m/s. Find the speed of the center of mass. Answer in units of m/s. Answer in units of m/s part 2 of 2 Find the magnitude of the total momentum of the system. Answer in units of Ns. Answer in units of N\s 1. 35.6937 2 47.8337 3. 7.22793 4. 7.82225 5. 31.4571 6. 20.7598 * 7. 6.46165 8. 10.5165 9. 10.3768 10. 8.21867 1. 49.8341 0 2 121.269 3. 52.7951 4. 28.7523 5. 28.3772 6.40.3032 7. 69.8296 8-106.699