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answerhappygod
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020 10.0 points A descending elevator of mass 670 kg is uni- formly decelerated to rest over a distance of 8 m by a cable in which the tension is 8656 N. The acceleration due to gravity is 9.8 m/s². V = Vi T 8 m Cable 670 kg Elevator v=05 Calculate the speed v; of the elevator at the
beginning of the 8 m descent. Answer in units of m/s.
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