Example III page 8: 1. 5.17 g of fertilizer was added to a 250.0 mL volumetric flask and water was added to make it up t

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Example III page 8: 1. 5.17 g of fertilizer was added to a 250.0 mL volumetric flask and water was added to make it up t

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Example Iii Page 8 1 5 17 G Of Fertilizer Was Added To A 250 0 Ml Volumetric Flask And Water Was Added To Make It Up T 1
Example Iii Page 8 1 5 17 G Of Fertilizer Was Added To A 250 0 Ml Volumetric Flask And Water Was Added To Make It Up T 1 (29.53 KiB) Viewed 16 times
Example III page 8: 1. 5.17 g of fertilizer was added to a 250.0 mL volumetric flask and water was added to make it up to the mark. 2. 20.00 mL of this solution was pipetted into a conical flask. 3. A slight excess of precipitating agent was added to precipitate the phosphate ions as MgNH₂PO4. 4. The precipitate was filtered, washed with water and then converted by heating into Mg P₂0 5. The mass of Mg₂P₂O7 was 0.0312 g Calculate the percentage by mass of phosphate in the fertilizer. Ans%(PO³)=6.42% Solution: mass of fertilizer = 5.17 g mass of Mg2P207 = 0.0312 g 2 PO4³- Total volume = 250.0 mL Used Volume = 20.00 mL Mg₂P₂07 0.0312 g
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