What is the [HA] (in mol L-¹) of a solution containing 1.464 mol L-¹ of a diprotic acid with PKA1 = 4.41 and PKA2 = 8.42

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answerhappygod
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What is the [HA] (in mol L-¹) of a solution containing 1.464 mol L-¹ of a diprotic acid with PKA1 = 4.41 and PKA2 = 8.42

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What Is The Ha In Mol L Of A Solution Containing 1 464 Mol L Of A Diprotic Acid With Pka1 4 41 And Pka2 8 42 1
What Is The Ha In Mol L Of A Solution Containing 1 464 Mol L Of A Diprotic Acid With Pka1 4 41 And Pka2 8 42 1 (7.44 KiB) Viewed 9 times
What is the [HA] (in mol L-¹) of a solution containing 1.464 mol L-¹ of a diprotic acid with PKA1 = 4.41 and PKA2 = 8.42 ? Answer: H₂A + H₂O = H₂O* + HA HA + H₂O = H₂O+ + A²- PKA1 PKA2
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