Given the following reaction at equilibrium, if Kc = 1.90 x 1019 at 25.0 °C, Kp =- H2 (g) + Br2 (g) → 2 HBr (g) OA-6.44

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answerhappygod
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Given the following reaction at equilibrium, if Kc = 1.90 x 1019 at 25.0 °C, Kp =- H2 (g) + Br2 (g) → 2 HBr (g) OA-6.44

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Given The Following Reaction At Equilibrium If Kc 1 90 X 1019 At 25 0 C Kp H2 G Br2 G 2 Hbr G Oa 6 44 1
Given The Following Reaction At Equilibrium If Kc 1 90 X 1019 At 25 0 C Kp H2 G Br2 G 2 Hbr G Oa 6 44 1 (12.82 KiB) Viewed 11 times
Given the following reaction at equilibrium, if Kc = 1.90 x 1019 at 25.0 °C, Kp =- H2 (g) + Br2 (g) → 2 HBr (g) OA-6.44 x 105 OB 1.90 × 1019 OC. 1.56 × 104 OD.5.26 × 10-20
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