If A Person Of Mass M Simply Moved Forward With Speed V His Kinetic Energy Would Be Mv2 However In Addition To Possess 1 (92.47 KiB) Viewed 11 times
If A Person Of Mass M Simply Moved Forward With Speed V His Kinetic Energy Would Be Mv2 However In Addition To Possess 2 (22.12 KiB) Viewed 11 times
If a person of mass M simply moved forward with speed V, his kinetic energy would be MV2 However, in addition to possessing a forward motion, various parts of his body (such as the arms and legs) undergo rotation. Therefore, his total kinetic energy is the sum of the energy from his forward motion plus the rotational kinetic energy of his arms and legs. The purpose of this problem is to see how much this rotational motion contributes to the person's kinetic energy. Biomedical measurements show that the arms and hands together typically make up 12% of a person's mass, while the legs and feet together account for 35%. For a rough (but reasonable) calculation, we can model the arms and legs as thin uniform bars pivoting about the shoulder and hip, respectively. In a brisk walk, the arms and legs each move through an angle of about 30° (a total of 60°) from the vertical in approximately 1 second. We shall assume that they are held straight, rather than being bent, which is not quite true. Let us consider a 75 kg person walking at 5.5 km/h having arms 69 cm long and legs 95 cm long.
Y Part B Using the average angular velocity from Part A, calculate the amount of rotational kinetic energy in this person's arms and legs as he walks. Express your answer in joules. Krot= Submit 15. ΑΣΦ Previous Answers Request Answer INIC ? * Incorrect; Try Again; 4 attempts remaining Pearson J
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