59 1 cos²x 2 sec’ - dx = [sec² xdx

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answerhappygod
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59 1 cos²x 2 sec’ - dx = [sec² xdx

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59 1 Cos X 2 Sec Dx Sec Xdx 1
59 1 Cos X 2 Sec Dx Sec Xdx 1 (15.61 KiB) Viewed 8 times
59 1 cos²x 2 sec’ - dx = [sec² xdx
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