- C 1h23 C 1 H23 1 M Cpba Ch Cl 73 2 T Bume Sici Imidazole Dmf 83 Oh 4 Oh 6 1 Na C6h 31 2 Ipc Bh Then H 1 (123.96 KiB) Viewed 13 times
2. Why the reagent is chosen instead of others?
3. What product will be formed if the other similar?
Thank you.....
C₁1H23 C₁1 H23 1. m-CPBA, CH₂Cl₂, 73% 2. t-BuMe,SICI, imidazole, DMF, 83% OH 4 OH 6 1. Na/C6H₁31 2. (+)-(IPC)₂BH then H₂O₂ 65% C₁1H23 C6H₁3 OSiMe₂t-Bu C6H₁3 1. HF, CH₂CN, 94% 2. NaOH, EtOH/H₂O 50 °C, 4 h, 99% 9 1 LOH C6H₁3 C₂H13 PhCO₂H, DEAD, PPh 3, 72% 2.5% KOH/MeOH, 50 °C, 3h, 62% 1. (COCI)₂, DMSO then Et₂N, 89% 2. HF, 71% C₁1H23 1. 8 3 -C6H₁3 OSiMe₂t-Bu 1. t-BuMe,SICI, imidazole, DMF, 90% 2. KOH, BnBr, dioxane, 81% 3. Cl₂CCNH(OBn), CF₂SO3H, 71% C₁₁ ₂23 CO₂H C6H₁3 www 1. N-Cbz-Leu, DCC, 85% 2. H₂, 10% Pd/C, THF 3. ACOCHO, THF, 72% 5 (C₁1H23)2 Cu(CN)Li₂ Et₂O, -20 °C, 2 h, 68% (regioselective) C6H₁3 OSiMe₂t-Bu C11H₂3 7 C11H23 2 m-CPBA CH₂Cl₂, 73% QBn QSiMe t-Bu simene CO₂Bn NH CHO 1. PhSO₂Cl, pyr 69% 2. H₂, 10% Pd/C, THF, 95% 10 (regioselective) C6H13 OH C₂H13 C6H13