Question 15 (5 points) Use the following theoretical equation 3 A₂B + 6 CD --> 6 AD+3 C₂B (OR 3 A₂ B +6CD right arrow 6

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Question 15 5 Points Use The Following Theoretical Equation 3 A B 6 Cd 6 Ad 3 C B Or 3 A B 6cd Right Arrow 6 1 (38.12 KiB) Viewed 9 times

Question 15 (5 points) Use the following theoretical equation 3 A₂B + 6 CD --> 6 AD+3 C₂B (OR 3 A₂ B +6CD right arrow 6 AD+3 C₂ B) Calculate the number of molecules of AD formed from the reaction of (2.3000x10^1) grams of A₂B and (2.1860x10^3) grams of CD The atomic weight of A is 15.0 grams/mol The atomic weight of B is 50.0 grams/mol The atomic weight of C is 35.0 grams/mol The atomic weight of D is 120.0 grams/mol Avogadro's number is (6.022x10^23) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Answer Question 16 (5 points) Use the following theoretical equation AB₂+2 C-2 CB+ A (OR A B₂+2 C right arrow 2 C B + B) Calculate the number of molecules of A formed from the reaction of (8.0000x10^1) grams of AB₂ and (6.150x10^2) grams of C The atomic weight of A is 15.0 grams/mol The atomic weight of B is 50.0 grams/mol x10 The atomic weight of C is 35.0 grams/mol Avogadro's number is (6.0220x10^23) Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: Answer Answer x10 Question 17 (5 points) Consider the following hypothetical equation. 3A+2B --> A₂B3 OR 3 A +2 Bright arrow A₂B3 The atomic weight of A is 25.0 g/mol The atomic weight of B is 50.0 g/mol Calculate the percent yield of AB if 20.0 grams of A₂B is produced from the reaction of 28.0 grams of A and 47.0 grams of B. Do not type units with your answer. Your Answer: