(1 point) A spring with a 10-kg mass and a damping constant 6 can be held stretched 2.5 meters beyond its natural length

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1 Point A Spring With A 10 Kg Mass And A Damping Constant 6 Can Be Held Stretched 2 5 Meters Beyond Its Natural Length 1 (105.91 KiB) Viewed 17 times

(1 point) A spring with a 10-kg mass and a damping constant 6 can be held stretched 2.5 meters beyond its natural length by a force of 5 newtons. Suppose the spring is stretched 5 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c² - 4mk? -44 m²kg²/sec² help (numbers) Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t with the general form C₁ eat cos(ßt) + C₂ ert sin(St) α= -6/20 ß = = sqrt11/10 Y = -6/20 8 = = sqrt11/10 C1 = 5 C2 = -3/sqrt11 help (numbers) help (numbers) help (numbers) help (numbers) help (numbers) help (numbers)