A production operation has six workstations. Stations 1, 2, and 3 are in parallel, and stations 4, 5, and 6 are in serie

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899603
Joined: Mon Aug 02, 2021 8:13 am

A production operation has six workstations. Stations 1, 2, and 3 are in parallel, and stations 4, 5, and 6 are in serie

Post by answerhappygod »

A production operation has six workstations. Stations 1, 2, and3 are in parallel, and stations 4, 5, and 6 are in series. A queuemay form behind each station. Jobs arrive uniformly between 1 and20 minutes apart to be processed. From the receiving station, ittakes 2 minutes to travel to one of the parallel stations. A jobselects one of Stations 1, 2, or 3 at random. The processing timeat the parallel stations is exponential with a mean of 27 minutes.It takes 1 minute to transfer from the parallel to series stationsand 1 minute to transfer between the series stations and to theexit station. The processing times for stations 4, 5, and 6 aregiven by normal distributions with means of 7, 8, and 9 minutes,respectively and standard deviations of 1 minute in all cases.Simulate the operation of the system for 40 hours afterinitializing the system for 8 hours.
(a) Provide queueing and resource statistics for everystation.
(b) Tally the time in the system for all jobs. You can belowfind the model and experiment file of the system described. Pleasereview the files and fill in the blanks.
A Production Operation Has Six Workstations Stations 1 2 And 3 Are In Parallel And Stations 4 5 And 6 Are In Serie 1
A Production Operation Has Six Workstations Stations 1 2 And 3 Are In Parallel And Stations 4 5 And 6 Are In Serie 1 (209.54 KiB) Viewed 13 times
Model File 0$ CREATE, 1:UNIF (1,20): NEXT (1$); 1$ Time= 2$ 3$ 4$ 5$ 6$ ( 7$ 8$ 9$ 10$ 11$ ASSIGN: Job Type=DISC NS Job Type: M=SReceiving; ROUTE: STATION, QUEUE, SEIZE, DELAY: ): (.33,1,.66,2,1,3): Arrival RELEASE: ROUTE: 2, SEQ; $1-S6; M; 1, Other: M, 1: NEXT (6$); ),,Other: NEXT (7$); M, 1; 1, SEQ; STATION, TALLY: _), INT (Arrival Time), 1; DISPOSE: No; ); Experiment File PROJECT, "Final Exam- Q4", "SEK",, Yes, No, Yes, No, No, No, No, No, No, No, No; ATTRIBUTES: QUEUES: 1, Queuel, FirstInFirstOut,,AUTOSTATS (Yes,,): 2, Queue2, First InFirstOut,,AUTOSTATS (Yes,,): 3, Queue3, FirstInFirstOut,,AUTOSTATS (Yes,,): 4, Queue4, FirstInFirstOut,,AUTOSTATS (Yes,,): 5, Queue5, FirstInFirstOut,,AUTOSTATS (Yes,,): 6, Queue 6, First InFirstOut,, AUTOSTATS (Yes,,); RESOURCES: 1, Machinel, Capacity (1),,Stationary, COST (0.0, 0.0, 0.0),,AUTOSTATS (Yes,,): 2, Machine2, Capacity (1),,Stationary, COST (0.0, 0.0, 0.0),,AUTOSTATS (Yes,,): 1, Proc Time, DATATYPE (Real): 2, Arrival Time, DATATYPE (Real): 3, Job Type, DATATYPE (Real); 3, Machine3, Capacity (1),,Stationary, COST (0.0, 0.0, 0.0),,AUTOSTATS (Yes,,): 4, Machine4, Capacity (1),,Stationary, COST (0.0.0.0, 0.0),, AUTOSTATS (Yes,,): 5, Machine5, Capacity (1),,Stationary, COST (0.0, 0.0, 0.0),, AUTOSTATS (Yes,,): 6, Machine 6, Capacity (1),,Stationary, COST (0.0, 0.0, 0.0),,AUTOSTATS (Yes,,); STATIONS: 1, S1,,,, AUTOSTATS (Yes,,): 2, S2,,,, AUTOSTATS (Yes,,): 3, S3,,,,AUTOSTATS (Yes,,): TALLIES: 4, S4,,,, AUTOSTATS (Yes,,): 5, S5,,,, AUTOSTATS (Yes,,): 6, S6,,,, AUTOSTATS (Yes,,): SEQUENCES: 1, Seq1, S1, Proc Time=Proc Time Parallel &$4, Proc Time=NORM (7,1) &$5, Proc Time Proc Time S5&S6, Proc Time=Proc Time S6 & SExit: DSTATS: 7, SExit,,,,AUTOSTATS (Yes,,): 8, SReceiving,,,,AUTOSTATS (Yes,,); 2, Seq2, S2, Proc Time=Proc Time. Parallel &$4, Proc Time=Proc Time $4&S5, Proc Time=Proc Time $5&S6, Proc Time= Proc Time S6&SExit: 3, Seq3, S3, Proc Time-Proc Time Parallel & S4, Proc Time-Proc Time S4&S5, Proc Time=Proc Time $5&S6, Proc Time= Proc Time S6&SExit; 1, Type 1 Time In System: 2, Type 2 Time In System: 3, Type 3 Time In System; 1, NQ (1), S1 Queue Length: 2, NQ (2), S2 Queue Length: 3, NQ (3), S3 Queue Length: 4, NQ (4), S4 Queue Length: 5, NQ (5), S5 Queue Length: 6, NQ (6), S6 Queue Length: 7, NR (1), S1 Res Utilization: 8, NR (2), S2 Res Utilization: 9, NR (3), S3 Res Utilization: Utilization: 10, NR (4), S4 Res 11, NR (5), S5 Res Utilization: 12, NR (6), S6 Res Utilization; REPLICATE, 1,0.0,2880, Yes, Yes, 480,,, 24.0, Minutes, No, No,,, No , No; EXPRESSIONS: 1, Int Arr Time, DATATYPE (Native), UNIF (1, 20): 2, Proc Time Parallel, DATATYPE (Native), ( 3, Proc Time S4, DATATYPE (Native), NORM (7,1): 4, Proc Time S5, DATATYPE (Native), NORM (8,1): 5, Proc Time S6, DATATYPE (Native), NORM (9, 1);
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply