- Find The Actual Current In The Load Generator 1 And Generator 2 By Using The Per Unit System Of Measurement 1 (181.74 KiB) Viewed 16 times
FIND THE ACTUAL CURRENT IN THE LOAD, GENERATOR 1 AND GENERATOR 2 BY USING THE PER UNIT SYSTEM OF MEASUREMENT.
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FIND THE ACTUAL CURRENT IN THE LOAD, GENERATOR 1 AND GENERATOR 2 BY USING THE PER UNIT SYSTEM OF MEASUREMENT.
FIND THE ACTUAL CURRENT IN THE LOAD, GENERATOR 1 ANDGENERATOR 2 BY USING THE PER UNIT SYSTEM OFMEASUREMENT.
3.13. Draw an impedance diagram for the electric power system shown in Figure 3.32 showing all impedances in per unit on a 100-MVA base. Choose 20-kV as the voltage base for generator. The three-phase power and line-line ratings are given below. 90 MVA 80 MVA 80 MVA 90 MVA G₁ G₁: T₁: T2: G₂: Line: Load: T₁ 38 20 kV 20/200 kV 200/20 kV 18 kV 200 kV 200 kV Load X - 9% - X = 16% X = 20% X = 9% X 120 Ω S = 48 MW +j64 Mvar Line 2 T₂ 38 G₂
3.13. Draw an impedance diagram for the electric power system shown in Figure 3.32 showing all impedances in per unit on a 100-MVA base. Choose 20-kV as the voltage base for generator. The three-phase power and line-line ratings are given below. 90 MVA 80 MVA 80 MVA 90 MVA G₁ G₁: T₁: T2: G₂: Line: Load: T₁ 38 20 kV 20/200 kV 200/20 kV 18 kV 200 kV 200 kV Load X - 9% - X = 16% X = 20% X = 9% X 120 Ω S = 48 MW +j64 Mvar Line 2 T₂ 38 G₂