- 5 For The Following Feedback System We Have G S R S K S 2 S 4 S 10 A B 10 Ge S Gp S Y S Where A Is The L 1 (196.27 KiB) Viewed 18 times
5. For the following feedback system, we have: G₂(s)= R(s) K (s+2) s+4+- (s+10) A+B 10 Ge(s) Gp(s) Y(s) where A is the last digit and B is the second last digit in your student number. (a) Find the closed loop poles and the control gain K that makes the system have 18% overshoot when Gc(s)=1. (b) Using the pole-zero cancellation method, dessign a lead compensator Ge(s)=(s+2)/(s+pe) that can reduce half of the settling time of the uncompensated syttem. Find the new control gain K of the lead compensator. (c) Compare the steady state errors of the compensated and uncompensated systems for a unit step input. (10 marks)