B Now Use Simulink To Simulate The Above Problem 1 Plot The Relationship Between Time X Axis And Displacement Y 1 (70.96 KiB) Viewed 61 times
B Now Use Simulink To Simulate The Above Problem 1 Plot The Relationship Between Time X Axis And Displacement Y 2 (50.77 KiB) Viewed 61 times
B Now Use Simulink To Simulate The Above Problem 1 Plot The Relationship Between Time X Axis And Displacement Y 3 (27.05 KiB) Viewed 61 times
(B) Now use Simulink to simulate the above problem. [1] Plot the relationship between time (x-axis) and displacement (y-axis) as t changes from 0 s to 10 s (7.5 marks) [2] Plot the relationship between time (x-axis) and velocity (y-axis) as t changes from 0 s to 10 s (7.5 marks) [3] Plot the relationship between time (x-axis) and acceleration (y-axis) as t changes from Os to 10s (7.5 marks) Upload your Simulink file as along with a PDF file of all the above three plots (displacement, velocity, and acceleration versus time) to the submission link in the BBL. (C) Now use Matlab to solve the above problem. [1] Plot the relationship between time (x-axis) and displacement (y-axis) ast changes from 0 s to 10 s (7.5 marks) [2] Plot the relationship between time (x-axis) and velocity (y-axis) ast changes from Os to 10 s (7.5 marks) [3] Plot the relationship between time (x-axis) and acceleration (y-axis) ast changes from Os to 10s (7.5 marks) Upload your Simulink file as along with a PDF file of all the above three plots (displacement, velocity, and acceleration versus time) to the submission link in the BBL. (D) Discuss the above results from Matlab and simulink (10 marks)
In the below figure, me = 6 kg, ma=18 kg, the mass (A) released from rest at time t=0 s. The mass A will move down, while mass B will move up on the inclined surface in the y-direction. E с D B X А 60° (A) Solve the above problem and prove the following: (10 marks)
(10 (A) Solve the above problem and prove the following: (2.6 x mg - m) ) ap = 9 (-MA – 3 x me vp=*= -ma 3 x mp) (2.6 x mg - m) XC (2.6 x mg - m) ? Displacement = y = * 4 - 2 A – 3 x me) 13
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