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1) Evaluate the following integral as a function of t: 1 ezt = 2π₁ Sc ²² (z ² + a²)d -dz where C is a positively oriente
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1) Evaluate the following integral as a function of t: 1 ezt = 2π₁ Sc ²² (z ² + a²)d -dz where C is a positively oriente
1) Evaluate the following integral as a function of t: 1 ezt = 2π₁ Sc ²² (z ² + a²)d -dz where C is a positively oriented circle, centered at the origin, with radius R > a 2) Show that if C is the positively oriented circle of unit radius, then for any real constant 'a', And therefore 1 = -TT fe e az Z -dz = 2 ni a cose cos(asine)d0 = π