Calculate the theoretical yield of CO2 in moles and in grams using the equations in the background as needed, and record

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Calculate the theoretical yield of CO2 in moles and in grams using the equations in the background as needed, and record

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Calculate the theoretical yield of CO2 in moles and in grams using the equations in the background as
needed, and record in Data Table 4.
Calculate The Theoretical Yield Of Co2 In Moles And In Grams Using The Equations In The Background As Needed And Record 1
Calculate The Theoretical Yield Of Co2 In Moles And In Grams Using The Equations In The Background As Needed And Record 1 (53.66 KiB) Viewed 10 times
Calculate The Theoretical Yield Of Co2 In Moles And In Grams Using The Equations In The Background As Needed And Record 2
Calculate The Theoretical Yield Of Co2 In Moles And In Grams Using The Equations In The Background As Needed And Record 2 (54.09 KiB) Viewed 10 times
200 Na + 100 Cl₂ → 200 NaCl Balancing atoms is not very practical on a macroscopic scale, so we employ the collective unit known as the mole, where one mole represents 6.02 x 1023 particles. So, considering the ability to scale 2(6.02 x 10²3) Na + (6.02 x 1023) Cl₂ → 2(6.02 x 10²³) NaCl This states that two moles of sodium plus one mole of chlorine react to make two moles of sodium chloride. Alternatively, we can use the collective term mole in place of atom or mole: 2 moles Na + 1 mole Cl₂ → 2 moles NaCl Or 2 mol Na + 1 mol Cl₂ → 2 mol NaCl In this exercise you will examine a series of reactions between sodium bicarbonate and 5% acetic acid (vinegar) to illustrate the concept of limiting reactants. The reaction occurs in two steps. The products of step 1 are sodium acetate and carbonic acid. Step 2, which occurs immediately after step 1, produces carbon dioxide and water. The balanced chemical equations for this reaction are: NaHCO3(s) + HC₂H3O₂(aq) → C₂H₂O₂Na(aq) + H₂CO3(aq) In this case, one reagent is in excess, that is, more is available than is necessary in the process. Therefore, the amount of the other reagent is limiting and when it is depleted, the reaction will cease. The limiting reagent will therefore dictate the maximum amount of product. We will isolate and compare the amount of copper formed as the yield Yield measrued amount of product X 100%

1 2 3 Data Table 2 Reaction # Reaction # 2 Data Table 3 32 Data Table 4 Reaction # 2 3 Volume of 5% Vinegar (mL) 5.0 mL 5.0 mL 5.0 mL 5.0 mL Mass of NaHCO, (g) 0.10g 0.20g 0.35g 0.50g Limiting Reactant Mass of HC₂H₂O₂ (g) (Vinegar) 0.25g 0.25g 0.25g 0.25g Moles of HC₂H₂O₂ (Vinegar) Theoretical yield of CO₂ (moles) 0.0042 mole 0.0042 mole 0.0042 mole 0.0042 mole Moles of NaHCO, 0.0017 mole 0.0024 mole 0.0042 mole 0.0059 mole Theoretical yield of CO, (g)
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