- The Equilibrium Constant K For The Reaction H G Br G 2 Hbr G Is 2 180 X 10 At 730 0 C Starting With 1 20 Mol 1 (22.4 KiB) Viewed 11 times
The equilibrium constant K, for the reaction H₂(g) + Br₂(g) 2 HBr (g) is 2.180 x 10° at 730.0 °C. Starting with 1.20 mol
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The equilibrium constant K, for the reaction H₂(g) + Br₂(g) 2 HBr (g) is 2.180 x 10° at 730.0 °C. Starting with 1.20 mol
The equilibrium constant K, for the reaction H₂(g) + Br₂(g) 2 HBr (g) is 2.180 x 10° at 730.0 °C. Starting with 1.20 moles of HBr in a 17.1 L reaction vessel, calculate the concentrations of H₂, Br, and HBr at equilibrium. Part: 0/2 Part 1 of 2 Be sure each of your answer entries has the correct number of significant digits. [H₂] - M [B₂]-M 0.2