- Starting Amount X How Many Moles Of Aluminum Are Required To Completely React With 107 Ml Of 6 00 M H So According To T 1 (31.88 KiB) Viewed 13 times
STARTING AMOUNT X How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO, according to t
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STARTING AMOUNT X How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO, according to t
STARTING AMOUNT X How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO, according to the balanced chemical reaction: Al(s) + 3 H₂SO,(aq)-Al(SO.),(aq) + 3 H₂(g) 08 ADD FACTOR 0.428 0.0374 98.08 1 2 mL H,SO, MH,SO. g H₂SO. mol H₂ 3 107 6.022 x 10 mol Al ANSWER 428 1000 RESET 6.00 2 0.001 0.963 g Al mol H₂SO. 9 Al(SO), LH,SO. mol Al(SO4) g H₂