4. For a voltaic cell based on the following half-reactions at 25 °C: Pb 2+ + 2e- à Pb 2+ Zn + 2e- à Zn E = -0.13 V Eº =

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4. For a voltaic cell based on the following half-reactions at 25 °C: Pb 2+ + 2e- à Pb 2+ Zn + 2e- à Zn E = -0.13 V Eº =

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4 For A Voltaic Cell Based On The Following Half Reactions At 25 C Pb 2 2e A Pb 2 Zn 2e A Zn E 0 13 V Eo 1
4 For A Voltaic Cell Based On The Following Half Reactions At 25 C Pb 2 2e A Pb 2 Zn 2e A Zn E 0 13 V Eo 1 (17.61 KiB) Viewed 21 times
4 For A Voltaic Cell Based On The Following Half Reactions At 25 C Pb 2 2e A Pb 2 Zn 2e A Zn E 0 13 V Eo 2
4 For A Voltaic Cell Based On The Following Half Reactions At 25 C Pb 2 2e A Pb 2 Zn 2e A Zn E 0 13 V Eo 2 (21.17 KiB) Viewed 21 times
4. For a voltaic cell based on the following half-reactions at 25 °C: Pb 2+ + 2e- à Pb 2+ Zn + 2e- à Zn E = -0.13 V Eº = -0.76 V Calculate Ece where [Pb 2] = 1.0 x 102 M and [Zn] =3.0 x 10² M. cell

3. A voltaic cell is based on the following half reactions at 25 °C: Ag+ e- à Ag E=0.8V H₂O₂ + 2H + 2e- à 2H,0 Predict whether E cell is larger or smaller than E for the following cases. Explain your cell answers. (a) [Ag ] 1.0 M, [H,O,] =2.0 M, [H]=2.0 M (b) [Ag ] Eº=1.78V 2.0 M, [H₂O₂] 1.0 M, [H] = 1.0 x 10" M
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