How much heat (in kJ) is needed to evaporate 1.8 moles of CCl4 (liquid) at its standard boiling point of 393 K? AS° vap

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How much heat (in kJ) is needed to evaporate 1.8 moles of CCl4 (liquid) at its standard boiling point of 393 K? AS° vap

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How Much Heat In Kj Is Needed To Evaporate 1 8 Moles Of Ccl4 Liquid At Its Standard Boiling Point Of 393 K As Vap 1
How Much Heat In Kj Is Needed To Evaporate 1 8 Moles Of Ccl4 Liquid At Its Standard Boiling Point Of 393 K As Vap 1 (31.33 KiB) Viewed 15 times
How much heat (in kJ) is needed to evaporate 1.8 moles of CCl4 (liquid) at its standard boiling point of 393 K? AS° vap for CCI 4 (liquid) = 94.0 J/(mol K). Express your answer with ONE decimal place. Type your answer...
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