3. A current-carrying wire has a resistivity of p= 1.72 x 10 m. It has a diamet D=0.0025 m and it is L= 0.5 m long. (20

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answerhappygod
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3. A current-carrying wire has a resistivity of p= 1.72 x 10 m. It has a diamet D=0.0025 m and it is L= 0.5 m long. (20

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3 A Current Carrying Wire Has A Resistivity Of P 1 72 X 10 M It Has A Diamet D 0 0025 M And It Is L 0 5 M Long 20 1
3 A Current Carrying Wire Has A Resistivity Of P 1 72 X 10 M It Has A Diamet D 0 0025 M And It Is L 0 5 M Long 20 1 (39.67 KiB) Viewed 42 times
3. A current-carrying wire has a resistivity of p= 1.72 x 10 m. It has a diamet D=0.0025 m and it is L= 0.5 m long. (20 points) L=0,5 m D-0.0025 mm) a) What is the resistance of the wire in ohms? b) If it is connected to a 9V power source, what is the current passing through wire? c) Current carrying wire produces a magnetic field around it. Considering this t a long wire find the magnitude of the magnetic field (B-field) at a distance 0 away. (= 4 x 10-7 Tm/A) d) If you create a circular loop (r= 0.25 m) with the same current carrying win find the magnetic field at the center of the loop. (H = 4 x 10-7 Tm/A) P-1.72 x 100m = 4. Consider the circuit shown below with the resistors. Let V 12V, R14, R2 = R3 110 and R4 = 1302 (20 points) +12V R1 40 www Loop 5 R2 80 www Loop? R4 13 Q ww R3 110 ww a. Considering the individual resistors (R1, R2, R3 and R4) find the equivalent resistance of the circuit b. If the current /₁ = 1.2A, using Kirchhoff's Laws find the current /₂ and 13 c. Find the power dissipation by each resistor R1, R2, R3 and R4 d. If the individual resistors were replaced by a single equivalent resistor with resistance found in part a, what would be the power dissipated by it.
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