for first half Q1= 10uc Q2=12uc

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answerhappygod
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for first half Q1= 10uc Q2=12uc

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for first half Q1= 10uc
Q2=12uc
For First Half Q1 10uc Q2 12uc 1
For First Half Q1 10uc Q2 12uc 1 (56.56 KiB) Viewed 49 times
For First Half Q1 10uc Q2 12uc 2
For First Half Q1 10uc Q2 12uc 2 (56.56 KiB) Viewed 49 times
Q2 +12V 14 7 12 C1 5 µF + C3 24uF 3 2 + (0, 0) Q1 3 a. What is the distance between Q1 and Q2? (The axis on the cartesian plane ar meters) 5M S S (S) TO b. What is the magnitude of the electrostatic force (Coulomb's force) that acts c the charge Q₂ by Q₁? (k = 8.99 x 10°⁹ Nm²/C²) O. 043 c. Find the magnitude and the direction angle (in degrees as measured from the negative x-axis) of the electric field at Q₂ location due to the presence of Q₁ Find the potential at Q₂ location due to Q₁ d. 534 Rai 2. Consider the circuit shown below with the capacitors (20 points) 514 2 3 3 μF + 5 senes 3²44² = (² 9116=25 -5 F=8-99X10 a. Find the total capacitance of the circuit b. Assume you made your own parallel plate capacitor which has a total capacitance equivalent to what you found in part a. If the area of the plates y are using is 0.1 m², find the distance you must maintain between the plates. (0 = 8.85 x 10-12) m c. If you connect your capacitor directly to a 12V supply, find the charge it will store. d. Find the energy that can be stored in your capacitor
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