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answerhappygod
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(10 out of 20 points) In the first stage of the tin carbothermic reduction, a smelting process converts 1 ton per hour of concentrated tin ore, which consists of SnO₂ (20 wt. %), SiO₂ (40 wt. %) and Fe2O3 (40 wt. %), to crude tin (Sn with Fe impurities) and a slag composed of solely SnSiO3 and FeSiO3. The crude tin metal contains 95 wt. % tin and 5 wt. % iron. The processing route for this process is presented below: Question 2 - Tin carbothermic reduction 0₂ SiO2, SnO₂, Fe₂O3 SnO The reaction basis of the smelting reactor is provided below: Reaction 1: Reaction 2: Reaction 3: Reaction 4: Reaction 5: Reaction 6: CO₂ Sn, Fe SnSiO3 + Fe₂SiO4 In this process, the components are reduced by carbon monoxide formed from the high temperature oxidation of metallurgical coke by oxygen. About 0.1 ton of coke per ton of concentrate is required. Some gaseous SnO is produced in the reactor, but a recirculation connection allows the separation of this gaseous SnO from the CO2 generated by the process for recirculation with the initial ore feed. SnO₂ + CO (g) → CO₂ (g) + SnO (g) SnO₂ + CO (g) + SiO₂ → SnSiO3 + CO₂ (g) Fe2O3 + CO (g) +SiO₂ → Fe2 SiO4 + CO₂ (g) C + 1/2O₂ (g) → CO (g) SnSiO3 + C → Sn + SiO₂ + CO (g) Fe2 SiO4 + 2 C 2 Fe + SiO2 + 2 CO (g) For this problem, you need to solve the problem by classical pen-and-paper methods (e.g., elimination of variable).
(10 out of 20 points) In the first stage of the tin carbothermic reduction, a smelting process converts 1 ton per hour of concentrated tin ore, which consists of SnO₂ (20 wt. %), SiO₂ (40 wt. %) and Fe2O3 (40 wt. %), to crude tin (Sn with Fe impurities) and a slag composed of solely SnSiO3 and FeSiO3. The crude tin metal contains 95 wt. % tin and 5 wt. % iron. The processing route for this process is presented below: Question 2 - Tin carbothermic reduction 0₂ SiO2, SnO₂, Fe₂O3 SnO The reaction basis of the smelting reactor is provided below: Reaction 1: Reaction 2: Reaction 3: Reaction 4: Reaction 5: Reaction 6: CO₂ Sn, Fe SnSiO3 + Fe₂SiO4 In this process, the components are reduced by carbon monoxide formed from the high temperature oxidation of metallurgical coke by oxygen. About 0.1 ton of coke per ton of concentrate is required. Some gaseous SnO is produced in the reactor, but a recirculation connection allows the separation of this gaseous SnO from the CO2 generated by the process for recirculation with the initial ore feed. SnO₂ + CO (g) → CO₂ (g) + SnO (g) SnO₂ + CO (g) + SiO₂ → SnSiO3 + CO₂ (g) Fe2O3 + CO (g) +SiO₂ → Fe2 SiO4 + CO₂ (g) C + 1/2O₂ (g) → CO (g) SnSiO3 + C → Sn + SiO₂ + CO (g) Fe2 SiO4 + 2 C 2 Fe + SiO2 + 2 CO (g) For this problem, you need to solve the problem by classical pen-and-paper methods (e.g., elimination of variable).