- 3 Connect The 0 22uf Capacitor In Parallel With The Inductor L 100mh As Below Channel 1 V 5 Vrms 1 1 Khz R 680 L 1 (45.27 KiB) Viewed 94 times
3. Connect the 0.22uF capacitor in parallel with the inductor L=100mH as below: Channel 1 V = 5 Vrms 1 = 1 kHz R-680 L =
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
3. Connect the 0.22uF capacitor in parallel with the inductor L=100mH as below: Channel 1 V = 5 Vrms 1 = 1 kHz R-680 L =
3. Connect the 0.22uF capacitor in parallel with the inductor L=100mH as below: Channel 1 V = 5 Vrms 1 = 1 kHz R-680 L = 100 m C=0.22 AF -W Runde = 100 Channel 2 4. Calculate and record the following circuit values: х х I IR Ic IX I Z PF Real Power Apparent Power 5. Construct the circuit above at the breadboard including the 0.22 pF capacitor. Adjust the applied voltage, VA to exactly 5 Vrms. With a DMM & OSC, measure and record the following circuit values: 1 IR Ic 4 Ix Real Apparent PF Power Power Calculate as per of Measured values 6. Provide screen shot for the circuit diagram at board.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!