- E 6 9 10 100 Mm0 40 001 M 3 10 0 0 0 10 1 2 Ac Eigenvals Kh 1 2 104 0 I 5 2 10 6 K J 0 1 2 6 727 4 1 (47.83 KiB) Viewed 22 times
E = 6.9-10⁹ [100 Mm0 40 001 M - 3-10 0 0 0 10,1..2 Ac = eigenvals (Kh) 1.2.104 0 I := 5.2-10-6 K = j=0,1..2 6.727 -[] 4.485 0 0 8.97-10 00 E-I L³ 0 0 3.10 M₁=√₁ 4.485 -2.242 0 Kh:= Mr!K/Mr"! Kh=|-2.242 2.242 2,242 0 -2.242 4.485 12 = Mr²¹ V₂ 2₂ = 4.495 00₂ = √√x₂0₂ = 2.118 A₂6.727 00₂, = √2₂ 10₂ = 2.594 [-0.707 v₂ = eigenver (Kh, A₂) P1 = augment (₁₂) P = augment (P1, V₂) го 00 о 0 0 0.013 The normalized mode shapes are 113 = Mr¹v₂ 3 -3 0 -3 6 -3 0 -3 3 ₂-0 2₁ = 0 0.707 ul := Mr¹v₁ uln= 3 = 32 = m = 3000 K-1.346 104 0 u2n = u3n = ul |ul| 1.346 10 -1.346 10¹ C = 0.002 K 9₁ = √√ v₂ = eigenvec (Kh, A₂) AC₂,2 2-00₂ 113 13 2.082 112 |12| ₁ = eigenver (Kh,^₁] <= A1,12=2.118-10 L = 2 0 2.691 104 -1.346-10 -1.346 10 1.346 104 Ch := Mr¹(c-Mr¹) Ac :=p² Ch.P uln= ²n = $32.594-10 u3n = 0.577 0.577 0.577 0.408 ₁=0.816 0.408 -0.707 0 0.707 0.667 -0.333 0.667 1₂ 0.577 = -0.577 0.577