A P1=20KN B 1.5m q LBC 150 I 12 150 Fig. 2a. Beam "ABCD" (for Q2) 300 20 P2=10KN 20 C 1m Fig. 2b Beam section for "ABCD"

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answerhappygod
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A P1=20KN B 1.5m q LBC 150 I 12 150 Fig. 2a. Beam "ABCD" (for Q2) 300 20 P2=10KN 20 C 1m Fig. 2b Beam section for "ABCD"

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A P1 20kn B 1 5m Q Lbc 150 I 12 150 Fig 2a Beam Abcd For Q2 300 20 P2 10kn 20 C 1m Fig 2b Beam Section For Abcd 1
A P1 20kn B 1 5m Q Lbc 150 I 12 150 Fig 2a Beam Abcd For Q2 300 20 P2 10kn 20 C 1m Fig 2b Beam Section For Abcd 1 (84.97 KiB) Viewed 28 times
A P1 20kn B 1 5m Q Lbc 150 I 12 150 Fig 2a Beam Abcd For Q2 300 20 P2 10kn 20 C 1m Fig 2b Beam Section For Abcd 2
A P1 20kn B 1 5m Q Lbc 150 I 12 150 Fig 2a Beam Abcd For Q2 300 20 P2 10kn 20 C 1m Fig 2b Beam Section For Abcd 2 (13.87 KiB) Viewed 28 times
A P1=20KN B 1.5m q LBC 150 I 12 150 Fig. 2a. Beam "ABCD" (for Q2) 300 20 P2=10KN 20 C 1m Fig. 2b Beam section for "ABCD" (unit: mm) D please (1) Draw shear force diagram and bending moment diagram for this beam (12 Marks) (2) If the beam section is shown in Fig. 2b, please calculate Ix-x (the second moment of inertia area) for the section (6 Marks) (3) Please calculate the maximum tensile stress and maximum compressive stress for this beam and indicate the location of the maximum stress points (8 marks) (4) Please calculate the maximum shear stress on the beam and indicate the location of the maximum stress point (8 marks)
Q2. A simply-supported beam "ABCD" is shown as below, where "A" is a pinned support, "D" is a roller suppport. Lbc = 4.4 and The uniformly distributed load (UDL) q = 3.5 is applied through the whole beam span, concentrate forces P1 and P2 are acting at B, C point.
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