G 100 V Ra 2.7k0 www B Rc 3.6km Re 10 www -2 V VEE Figure 3 C 가 D Vout RL 100km i. ii. Describe what is emitter current

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G 100 V Ra 2.7k0 www B Rc 3.6km Re 10 www -2 V VEE Figure 3 C 가 D Vout RL 100km
i. ii. Describe what is emitter current distortion? Why the operating point (Q-point) of an amplifier is chosen to be located at the center of the loadline? [4 Marks] [C3] To avoid current distortion, we make sure to use the amplifier in small signal operation. Calculate the maximum peak-to-peak emitter current, ie(p-p). (Rules: le(p-p) < 0.1 IEQ) [4 Marks] [C3]
iii. State THREE characteristics of the circuit configuration in Figure 3 (baiasing? Function of the capacitors?). iv. [6 Marks] [C3] What is the difference between coupling capacitors and bypass capacitors? For a frequency of v, is at 50 Hz, verify if the coupling and bypass capacitors are well chosen. (Rules: X < 0.1R) [8 Marks] [C3]
(b) For the circuit shown in Figure 3, calculate and plot the voltages at point A, B, C, D, and Vout- Draw an equivalent 7 model of the amplifier. [5 Marks] [C4] [3 marks] [C3]