The Circuits The Computed Answer 1 (43.83 KiB) Viewed 31 times
The Circuits The Computed Answer 2 (34.4 KiB) Viewed 31 times
The computed answer:
The Circuits The Computed Answer 3 (31.52 KiB) Viewed 31 times
DC Analysis A Vcc Vcc Vcc 5V www base in Vcc Vcc R1 5.60k0 R2 2.20k0 RC 1.8K0 Pollector_out PR2 Q2 v 2.9782V / 1.1232mA 2N3904G RE 6800 v 770.24mV 1.1327mA
AC Analysis =Vcc TO SV v-9.6858mV i-5.4307μA R3 PR1 A Vcc Vcc in V1 10.0mV 10kHz 0° C1 wh 56092 4.7μF www A Vcc Vcc www R1 5.60k base in R2 2.20kΩ RC 1.8kQ collector out 2 0 Q2 2N3904G RE 68092 C2 HH 22μF v 264.90mV PR2 26.490μA CE 10μF out RL 10kg 4
DC Conditions of the Circuit are VC=2.9782Volts and VE=770.24mV IC= 1.123mA and IE= 1.132mA AC conditions Output Voltage VO=264.90mV for Vin=-9.68mV Voltage gain = 27.365 Output Current=26.490 UA input Current=5.4uA Current Gain=5 And From Simulation input and Output Voltages are 180 Degrees Out of Phase Komp 12.
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