Suppose Tony and Rita are racing. Tony starts 35 ft ahead of the starting line because he is slower than Rita. Tony's sp

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Suppose Tony And Rita Are Racing Tony Starts 35 Ft Ahead Of The Starting Line Because He Is Slower Than Rita Tony S Sp 1 (42.75 KiB) Viewed 42 times

Suppose Tony and Rita are racing. Tony starts 35 ft ahead of the starting line because he is slower than Rita. Tony's speed is 10 ft/s. Rita's speed is 15 ft/s. Let t represent the number of seconds that have elapsed since the start of the race. (a) What does the expression 15t tell you in terms of the race? O when Rita catches Tony O Tony's distance at time t O Rita's distance at time t O Rita's speed at time t O Tony's speed at time t (b) Write an equation to show the relationship between the time that has elapsed in the race and Tony's distance (in feet) from the starting line. (Used for distance and t for time.) d = 15t X (c) Write an equation to show the relationship between the time that has elapsed in the race and Rita's distance (in feet) from the starting line. (Used for distance and t for time.) d = 50 + 15t X (d) If you solved the equation 15t = 35 + 10t for t, what would you have found (in terms of the situation of the race)? O who wins the race O the time when Rita's and Tony's distances are equal O difference in Rita and Tony's speeds O difference in Rita and Tony's distance at any time t O when the race ends (e) Use algebra to find the time, in seconds, at which Rita will catch up to Tony. sec (f) How many feet will Tony have ran when Rita catches up to him? How far, in feet, will Rita have traveled? Tony's distance ft Rita's distance ft