- 4 A Chemistry 1411 Student Mixed 25 Grams Of Fe With 40 Grams Of H O The Balanced Equation For This Reaction Is 3fe S 1 (28.41 KiB) Viewed 76 times
4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H₂O. The balanced equation for this reaction is 3Fe(s)
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4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H₂O. The balanced equation for this reaction is 3Fe(s)
4. A chemistry 1411 student mixed 25 grams of Fe with 40 grams of H₂O. The balanced equation for this reaction is 3Fe(s) + 4H₂O(1) à Fe₂O4(s) + H2(g) An 95% yield of Fe,O, was obtained. a) What is the theoretical yield of Fe,O,? b) What is the limiting reactant in this experiment? grams (5 points) (2 points) c) What is the actual yield of Fe,O, if the reaction gave a 95% yield? grams (3 points)